Psychospace is the space where psychic things happen.
what is the probability that of the pre emptive dream numbers of g, the "miss x" who was set to pick 3 numbers, picked 2 of those by g.
Nearly 2% (i.e. a chance of 1 in about 50).
Here is the working:
First we consider the case where Miss X has one guess, and then we expand that to the case where she has 3 guesses.
To calculate the chance of guessing (in one guess) any of 4 numbers randomly chosen in the range (1...50), the easiest way is to calculate the chance of guessing wrong, and then to subtract that from 1.
The chance of guessing wrong is the chance that her guess is not the first number, and that it is not the second, and that it is not the third, and that it is not the fourth. Which is, (49/50) to the power of 4. Which is about 0.9224
i.e. there is an about 92% chance that her single guess is wrong. Thus there is an about 8% chance that it is right.
Now we consider the fact that she has three guesses.
It's easy to see the chance of all 3 being wrong: it is 92% cubed, which is about 78%. Likewise, the chance of all 3 guesses being right is 8% cubed, which is about .05% (i.e. a chance of 1 in about two thousand).
The chance of exactly one guess being right is the chance that her first guess is right and the other two are wrong, plus the chance that her middle guess is right and the other two are wrong, plus the chance that her last guess is right and the other two are wrong. That is 3 times 8% times 92% squared, which is about 20% (i.e. a chance of 1 in about five).
Likewise, the chance of exactly two guesses being right is the chance that her first guess is wrong and the other two are right, plus the chance that her middle guess is wrong and the other two are right, plus the chance that her last guess is wrong and the other two are right. That is 3 times 92% times 8% squared, which is about 1.8% (i.e. a chance of 1 in about 57).
Putting this all together, and expressing it (for convenience) in terms of Miss X repeating her 3-guess experiment 2000 times, we find the likelihood that
she would get none right about 1560 times (i.e. 78% chance)
she would get one right about 400 times (i.e. 20% chance)
she would get two right about 36 times (i.e. 1.8% chance)
she would get three right about 1 time (i.e. .05% chance)
Note as a double-check that 1560 plus 400 plus 36 plus 1 equals (approx) 2000
(actually it equals 1997; the difference is due to rounding error which we could reduce if we used more decimal places).
So in summary, Miss X would get 2 or more out of 3 guesses right about 37 times out of 2000
which is nearly 2%, or slightly less than a chance of 1 in 50
HTH (hope that helps).
So did she actually do that? If you say 'yes' I probably won't believe you. Wishing good luck with the antibiotics.